How much nitrogen-13 would be left after 40 minutes if the sample started at 4g

0.248 g

We are given;

We are required to calculate the amount left after decay.

We are going to use the formula;

That is; N = N₀ ×  0.5^n , where n is the number of half lives.

n = 40 minutes ÷ 9.965 minutes

  = 4.014

Therefore;

N = 4 g × 0.5^4.014

 = 0.248 g

Therefore, the mass of Nitrogen-13 that will be left is 0.248 g

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.