Asaline solution contains 1.6 % nacl by mass. how much nacl is present in 57.2 g of this solution?

0.92 g

Explanation:

Given data:

Percentage of NaCl = 1.6%

Amount of NaCl present in 57.2 g = ?

Solution:

1.6% of 57.2 g NaCl:

1.6/100× 57.2 g

0.92 g

So in 57.2 g 1.6% of NaCl is 0.92 g.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole