Balancing chemical equations place the number in the correct coefficient location to make each equation balance.

Explanation:

Balance Chemical Equation:

A balanced chemical equation is that in which the the number of the reactant atoms equal to the number of the product atom.

For example if the oxygen at the reactant side is 4, the number of oxygen should be 4 on the product side.

The complete answer is in attachment

Equation 1:

2 is the correct number

In the equation look for the number of Carbon on product side

C = 4 so it should be 4 on reactant side too

So,

by putting 2 in Coefficient location the number of C become equal on reactant as well as product side.

____________________

Equation 2:

12 on reactant side and 6 on product side is the correct number

In the equation look for the number of Hydrogen (H) on product side

it is H = 12 so it should be 12 on reactant side too

Then look for the number of Chlorine (Cl) on reactant side

C = 12 so it should be 12 on Product side too

So,

by putting 12 in Coefficient location of the reactant side and 6 on product side the number of H and Cl become equal on reactant as well as product side.

______________________

Equation 3:

5 is the correct number

In the equation look for the number of Oxygen on product side

O = 12 so it should be 12 on reactant side too

So,

by putting 5 in Coefficient location the number of O become equal on reactant as well as product side.

______________________

Equation 4:

3 on reactant side and 1 on product side is the correct number

In the equation look for the number of Chlorine (Cl) on product side

it is Cl = 6 so it should be 6 on reactant side too

Then look for the number of Calcium (Ca) on reactant side

Ca = 1 so it should be 1 on reactant side too

So,

by putting 3 in Coefficient location of the reactant side and 1 on product side the number of Cl and Ca become equal on reactant as well as product side.

____________________

Equation 5:

4 and 7 on reactant side is the correct number

In the equation look for the number of Sulfur (S) on product side

it is S = 4 so it should be 4 on reactant side too

Then look for the number of Oxygen (O) on product side

O = 14 so it should be 14 on reactant side too

So,

by putting 4 and 7 in Coefficient location of the reactant side so the number of S and O become equal on reactant as well as product side.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml