For the oxidation of glucose (ch 206 + 602 61,0 +6co2), how many grams of
oxygen gas will be consumed when 950 g of glucose is oxidized completely?

Mass = 1017.6 g

Explanation:

Given data:

Mass of glucose = 950 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 950 g/ 180 g/mol

Number of moles = 5.3 mol

Now we will compare the moles of oxygen and glucose.

           C₆H₁₂O₆        :              O₆

                1               :               6

                5.3          :             6×5.3 = 31.8 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 31.8 mol  ×  32 g/mol

Mass = 1017.6 g

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

first one is the correct answer