An aqueous solution of 10.03 g of catalase, an enzyme found in the liver, has a volume of 1.05 l at 27°c. the solution's osmotic pressure at 27°c is found to be 0.745 torr. calculate the molar mass of g/mol

Answer : The molar mass of catalase is,

Explanation :

Formula used :

where,

= osmotic pressure  = 0.745 torr = 0.000980 atm   (1 atm = 760 torr)

C = concentration

R = solution constant  = 0.0821 L.atm/mol.K

T = temperature  =

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution  = 1.05 L

Now put all the given values in the above formula, we get:

Therefore, the molar mass of catalase is,

1. they vary with a higher number because boiling is way hotter than melting