For the reaction shown here

8h2s(g) > < 8h2(g) + s8(g)

the equlibrium concentrations were found to be

[h2s] = 0.250 m
[h2] = 0.400 m
[s8] = 0.750 m

what is the equilibrium constant for this reaction?

kc =

The equilibrium constant for the reaction is 32.2

The equilibrium constant (K꜀) for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficients to the concentration of the reactants raised to their coefficients

With the above information, we can obtain the equilibrium constant for the reaction given above as follow:

8H₂S(g) <=> 8H₂(g) + S₈(g)

Concentration of Hydrogen sulphide [H₂S] = 0.250 M

Concentration of Hydrogen [H₂] = 0.400 M

Concentration of sulphur [S₈] = 0.750 M

Therefore, the equilibrium constant for the reaction is 32.2

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Kc = 32.3

Explanation:

To calculate the Kc, it's the ratio of products over reactants (each raised to their respective stoichiometric coefficient). In this case:

in theory, limestone is composed principally of the compound calcium carbonate - caco3, but in reality this compound is deposited in conditions involving a number of other compounds as impurities so it ends up being a mixture of many compounds.

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tony (lordcaos066)

a electronegativity decreases beacuse the size of nucleus is bigger.