Chemistry, 03.12.2019 23:31 ksweeny02

Consider the following equilibrium.2 nobr(g)< => 2 no(g) + br2(g)if nitrosyl bromide, nobr, is 34 percent dissociated at 25°c and the total pressure is 0.25 atm, calculate kp and kc for the dissociation at this temperature.

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Answer from: vaehcollier

$K_{p}$ of the reaction is $9.521 \times 10^{-3}$ .

$K_{c}$ of the reaction is $3.89 \times 10^{-4}$ .

Explanation:

Initial pressure of NOBr is "x" atm.

34% = 0.34

The equilibrium chemical reaction is a follows.

$2NOBr(g)\leftrightarrow 2NO(g)+Br_{2}(g)..............(1)$

Initial x 0 0

Change -0.34x +0.34x +0.17x

Final (x-0.34x) +0.34x +0.17x

Total pressure = sum of the pressure at equilibrium.

0.25atm=x-0.34x+0.34x+0.17x

0.25atm= 1.17x

$x= \frac{0.25}{1.17}=0.213$

Partial pressure of NOBr= x-0.34x =x (1-0.34)

= 0.213(0.66) = 0.14 atm.

Hence, partial pressure of $[]P_{NOBr}]$ is 0.14 atm.

$P_{NO}=0.34x = 0.34 \times 0.213 = 0.072$

$P_{Br_{2}}=0.17x = 0.17 \times 0.213 = 0.036\,atm$

From equation (1)

$K_{p}= \frac {P^{2}_{NO} P_{Br_{2}}}{P^{2}_{NOBr}}$

$= \frac{(0.072)^{2} (0.036)}{(0.14)^{2}}= 9.521 \times 10^{-3}$

Therefore, $K_{p}$ of the reaction is $9.521 \times 10^{-3}$ .

$K_{p}= K_{c}(RT)^{\Delta n}$

Rearrange the equation is as follows.

$K_{c}= \frac{K_{p}}{(RT)^{\Delta n}}$

$\Delta n$ = number of moles of reactants - Number of moles of products

= 3-2 = 1

$= \frac{9.521 \times 10^{-3}}{(0.0821 \times 298)^{1}}= 0.389 \times 10^{-3} = 3.89\times 10^{-4}$

Therefore, $K_{c}$ of the reaction is $3.89 \times 10^{-4}$ .

Answer from: Quest

water molecules stay close to each other through cohesion, the collective action of hydrogen bonds between water molecules. cohesion plants draw water upwards from the root through the stem's transport tubes (xylem) to the leaf. this transport occurs even in large trees and against gravity. transpiration, evaporation of water from plant leaves, creates a tension on water molecules being pulled up from the stem and roots.

water also has high (the attraction of one substance to another) properties because of its polar nature. adhesion of water molecules to plant cell walls counteract gravity while water is transported from roots to leaves.

water exhibits a very high surface tension when compared to other liquids. surface tension is a property of a liquid that holds the surface together and allows it to resist an external force. by capillary action, the water forms concave menisci inside the pores. the high surface tension of water pulls the concavity outwards, generating enough force to lift water from the roots to the leaves of plants.

thus, cohesion, along with adhesion and surface tension creates a capillary action that keeps water molecules interacting and moving through the plants out to the leaf cells.

therefore, option d) is the correct answer.

explanation:

Answer from: Quest

i dont know the answe

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Consider the following equilibrium.2 nobr(g)< => 2 no(g) + br2(g)if nitrosyl bromide, nobr, i...

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