Suppose work input is 25 j and the output distance is 10 m factoring in the effect of friction which must be true about output force a) it equals 2.5n b) it is less than 2.5n c) it is greater than 2.5n

Therefore F ∠ 2.5N

Explanation:

Definition of Work:

It is the amount of energy transferred.

Mathematical expression:

W = F × d

By taking the friction into count it will define as:

Input work = work against friction ×  output work

No we will put the values:

25 J = w + 10 m

j = kg m²/s²

25 kg m²/s² =  w + 10 m

when friction is exist then w > 0

25 kg m²/s² - 10 m  > 0

15 N > 0

Therefore F ∠ 2.5N

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answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.