What is the concentration (m) of a nacl solution prepared by dissolving 9.3 g of nacl in sufficient
water to give 350 ml of solution?

Molarity = 0.458M

Explanation:

Molarity is the representation of the solution.

Molarity:  

it is amount of solute in moles per litre of solution and represented by M

Formula used for Molarity

                      M = moles of solute / Litre of solution

Data Given:

NaCl = 9.3 g

volume of solution = 350 mL

volume of solution in litre = 350/1000

volume of solution = 0.35 L

Molarity = ?

Formula used to Calculate M

                      M = moles of NaCl / Litre of solution . . . . . . . . .  (1)

So

we have to first calculate moles of NaCl

                 Moles of NaCl = mass of NaCl/ Molar Mass (NaCl) . . . . . . .  (2)

*Molar Mass of NaCl = 58 g/mol

Put values in Eq (2)

                  Moles of NaCl = 9.3 g/ 58 g/mol

                  Moles of NaCl = 0.16 mol

Now

Put values in Eq (1)

                       M =  0.16 mol / 0.35 L

                       M = 0.458

So the Molarity = 0.458M

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