Achiral compound x has the formula c8h17br. y, c8h17cl, is chiral. x undergoes base-promoted e2 elimination to give a single alkene product z. under similar conditions y produces a mixture of alkenes, including z. catalytic hydrogenation of z affords 2-methylheptane. propose structures for x and y.

1-bromo-6-methylheptane : X

2-chloro-6-methylheptane: Y

Explanation:

A chiral compound is one which has a carbon with all four groups different.

Given:

Compound X is Achiral

Compound Y is chiral

Compound X gives single alkene on elimination : Z

Compound Y gives mixture of alkenes

Z on hydrogenation gives 2-methylheptane.

So the alkene must have carbon chain arrangement similar to 2-methylheptane and so the compound X and Y.

Based on the information the possible compounds are:

1-bromo-6-methylheptane : X

2-chloro-6-methylheptane: Y

The structures are shown in the figure.

the answer is barium and copper bromide

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