The gas-phase reaction follows an elementary rate law and is to be carried out first in a pfr and then in a separate experiment in a cstr. when pure a is fed to a 10 dm 3 pfr at 300 k and a volumetric flow rate of 5 dm 3 /s, the conversion is 80%. when a mixture of 50% a and 50% inert (i) is fed to a 10 dm 3 cstr at 320 k and a volumetric flow rate of 5 dm 3 /s, the conversion is also 80%. what is the activation energy in cal/mol

The activation energy is

Explanation:

The gas phase reaction is as follows.

The rate law of the reaction is as follows.

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" =

Temperature "T" = 300 K

Volumetric flow rate of the reaction

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

Rearrange the formula is as follows.

The feed has Pure A, mole fraction of A in feed is 1.

= change in total number of moles per mole of A reacte.

Substitute the all given values in equation (1)

Therefore, the rate constant in case of the plug flow reacor at 300K is

The rate constant in case of the CSTR can be calculated by using the formula.

The feed has 50% A and 50%  inerts.

Hence, the mole fraction of A in feed is 0.5

= change in total number of moles per mole of A reacted.

Substitute the all values in formula (2)

Therefore, the rate constant in case of CSTR comes out to be

The activation energy of the reaction can be calculated by using formula

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

Substitute the all values.

Therefore, the activation energy is

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .