The balanced combustion reaction for c 6 h 6 is 2 c 6 h 6 ( l ) 15 o 2 ( g ) ⟶ 12 co 2 ( g ) 6 h 2 o ( l ) 6542 kj if 7.700 g c 6 h 6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ c, what is the final temperature of the water

Explanation:

To calculate the moles, we use the equation:

According to stoichiometry :

2 moles of releases = 6542 kJ of heat

0.9858 moles of  release = of heat

Thus heat given off by burning 7.700 g of  will be absorbed by water.

Q = Heat absorbed= 3224kJ = 3224000J   (1kJ=1000J)

m= mass of water = 5691 g

c = specific heat capacity =

Initial temperature of the water = = 21.0°C

Final temperature of the water =  = ?

Putting in the values, we get:

The final temperature of the water is

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).