The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.0 x 10-5 s-1 at 10 km above the planet’s surface. consider a laboratory experiment in which a vessel of ozone is exposed to uv radiation at an intensity chosen to mimic the conditions at that altitude. if the initial o3 concentration is 5.0 x 10-3m, what will the concentration be after 10.0 day?

[O₃]= 8.84x10⁻⁷M  

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

(2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration    

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

(3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):  

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

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the answer is na (sodium)