Metal-x = molybdenum

metal-y = iron

metal-x forms a substitutional solid solution with metal-y. compute the number of metal-x atoms per cubic centimetier for a metal--x alloy that contains 33wt% metal-x and 67 wt% metal-y.

there are two Mo atoms per seven Fe atoms

Explanation:

The metal X = Molybdenum

Metal Y = Iron

The atomic weight of

Mo = 96 g/ mol

Fe = 56 g/mol

The weight ratio of given metals is

Mo = 33%

Fe =67%

Let us calculate the moles of each metal in 100g of sample.

Thus metal atom ratio =

Thus there are two Mo atoms per seven Fe atoms