Calculate the work associated with the compression of a gas from 121.0 l to 80.0 l at a constant pressure of 16.7 atm.

6.94 × 10⁴ J

Explanation:

We can calculate the work (W) associated with the compression of a gas at constant pressure using the following expression:

W = -P . ΔV

where,

P is the external pressure

ΔV is the change in the volume

Knowing that 1 atm.L = 101.325 J, the work of compression is:

The positive sign of the work means that the surroundings do work on the system.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.