How much calcium hypochlorite (65% strength) is needed to make 200 l of 2% hypochlorite solution? (assume that a 1% solution is equivalent to 10,000 mg/l concentration)

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

65 x V1 = 2 x 200 L

V1 = 6.15 L

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it should be p1 v1 = p2 v2