Add the following thermochemical equations: (1) p4(s) + 6cl2(g) => 4pcl3(g) δh = –1148 kj (2) 4pcl3(g) + 4cl2(g) => 4pcl5(g) δh =–460 kj (3) overall equation = ? δhoverall = ? select the correct δh for the overall process (equation 3)

the overall reaction is

P4(s) + 10Cl2(g)   => 4PCl5(g)

and its ΔH  is

ΔH overall =  (-1608 KJ)

Explanation:

given that

P4(s) + 6Cl2(g) => 4PCl3(g)  , ΔH1 = –1148 kJ

4PCl3(g) + 4Cl2(g) => 4PCl5(g) , ΔH2 =–460 kJ

summing both equation gives

P4(s) + 6Cl2(g) +4PCl3(g) + 4Cl2(g)   => 4PCl3(g)  +  4PCl5(g)

but 4PCl3(g) is in both sides , so is cancelled out

P4(s) + 6Cl2(g)+ 4Cl2(g)   => 4PCl5(g)

summing the Cl2(g)

P4(s) + 10Cl2(g)   => 4PCl5(g) → overall reaction

(can be verified that the reaction is balanced)

since we sum both equations the ΔH of the overall reaction is also the sum of the ΔH of the individual reactions.

ΔH  overall = ΔH1 + ΔH2 =  (–1148 kJ) + (–460 kJ) = (-1608 KJ)

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :