How many moles of iron (ii) iodine are produced when 112 grams of iron (ii) reacts with excess iodine?

2moles

Explanation:

The best way to solve this problem is to write a balance equation for the reaction.

Which is: Fe2 + 2i2> 2Fei2

With this you can see that iron ii reacting with excess iodine produces two (2) moles of iron ii iodine.

Alternatively.

Using the formular

Moles = reacting mass/molar mass

Reacting mass = 112g

Molar mass of iron ii = 55g/mol

Hence,

Mole = 112g divides 55g/mol

= 2.0mol//

i believe the answer is true.