1,000 kg of soya beans, of composition 18% oil, 35% protein, 10.5% moisture and 36.5% other contents
of carbohydrate ,fiber and ash are:
(a) crushed and pressed, which reduces oil content in beans to 6%;
(b) then extracted with hexane to produce a meal containing 0.5% oil;
(c) finally dried to 8% moisture.
assuming that there is no loss of protein and water with the oil, set out a mass balance for the soyabean
constituents.

Where's the pictures ?

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Answer: temperature? i hope this and have a wonderful