Asolenoid 2 cm long consists of 5653 loops of wire. if the magnetic field inside the solenoid is 4 t, what is the magnitude of the current that flows through it? a solenoid 2 cm long consists of 5653 loops of wire. if the magnetic field inside the solenoid is 4 t, what is the magnitude of the current that flows through it? 140 a 9.1×10−2 a 11 a 2.0 a

11 A

Explanation:

The magnetic field inside a solenoid can be calculated by the equation:

B = μ*(N/L)*i

Where B is the magnetic field, μ is the magnetic permeability (which is 1.256x10⁻⁶ T/m.A at vacuum), N is the number os loops, L is the length of the solenoid (2 cm = 0.02 m), and i the current.

4 = 1.256x10⁻⁶ *(5653/0.02)*i

0.355i = 4

i ≅ 11 A

false

because it does not have the potential to be entirely used up