Question 22 a mixture of krypton and argon gas is expanded from a volume of 33.0l to a volume of 61.0l , while the pressure is held constant at 58.0atm . calculate the work done on the gas mixture. be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Answer : The work done on the gas mixture is -164 kJ

Explanation :

Formula used :

where,

w = work done  = ?

p = pressure of the gas = 58.0 atm

= initial volume = 33.0 L

= final volume = 61.0 L

Now put all the given values in the above formula, we get:

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas mixture is -164 kJ

it is a solid

explanation: