Suppose you start with a solution of red dye #40 that is 2.3 ✕ 10−5 m. if you do three successive volumetric dilutions pipetting 3.00 ml of solution and diluting with water in a 25.00 ml volumetric flask, what is the molarity of the final dilution?

Therefore, the concentration of final solution is

Explanation:

According to the neutralization law,

where,

= molarity of stock solution =

= volume of stock solution = 3.00 ml

= molarity of diluted solution = ?

= volume of diluted solution = 25.00 ml

Therefore, the concentration of diluted solution is

2) On further dilution

where,

= molarity of stock solution =

= volume of stock solution = 3.00 ml

= molarity of diluted solution = ?

= volume of diluted solution = 25.00 ml

Therefore, the concentration of diluted solution is

3) On further dilution

where,

= molarity of stock solution =

= volume of stock solution = 3.00 ml

= molarity of diluted solution = ?

= volume of diluted solution = 25.00 ml

Therefore, the concentration of final solution is