Al2o3 + 6 hcl ↔ 2 alcl3 + 3 h2o if you start with 67.7 grams al2o3 and 196.8 grams hcl, how many grams of alcl3 can be produced by the reaction?

Mass = 177.34 g

Explanation:

Given data:

Mass of Al₂O₃ = 67.7 g

Mass of HCl = 196.8 g

Mass of AlCl₃ = ?

Solution:

Chemical reaction:

Al₂O₃ +6 HCl  →  2AlCl₃ + 3H₂O

Number of moles of Al₂O₃:

Number of moles = mass/ molar mass

Number of moles =   67.7 g / 101.96 g/mol

Number of moles = 0.664 mol

Number of moles of HCl:

Number of moles = mass/ molar mass

Number of moles =  196.8 g / 36.5 g/mol

Number of moles = 5.4 mol

Now we will compare the moles of AlCl₃  with HCl and Al₂O₃.

                       Al₂O₃       :        AlCl₃

                           1             :          2

                           0.664    :        2×0.664 = 1.33 mol

                        HCl          :           AlCl₃

                          6            :               2

                          5.4         :          2/6×5.4 = 1.8 mol

The number of moles produced by  Al₂O₃  are less so it will limiting reactant.

Mass of AlCl₃:

Mass = number of moles  × molar mass

Mass = 1.33 mol   ×  133.34 g/mol

Mass = 177.34 g

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.