What is the concentration in molarity of a solution made using 30.0 grams of ch3oh in 300.0 ml of water?
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This solution has a molarity of 3.12 M = 3.12 mol/ L

Explanation:

Step 1: Data given

mass of CH3OH = 30.0 grams

Volume of the solution = 300.0 mL = 0.3 L

Molar mass of CH3OH (see periodic table)

⇒ C = 12 g/mol

⇒ H = 1.01 g/mol

⇒ O = 16 g/mol

  ⇒ 1*12 + 4*1.01 + 16 = 32.04 g/mol

Step 2: Calculate number of moles of CH3OH

Moles CH3OH = mass CH3OH / Molar mass CH3OH

Moles CH3OH = 30.0 grams / 32.04 g/mol

Moles CH3OH = 0.936 mol

Step 3: Calculate molarity of the solution

Molarity of solution = moles CH3OH / volume of water

Molarity solution = 0.936 mol /0.300 L

Molarity of the solution = 3.12 M

This solution has a molarity of 3.12 M = 3.12 mol/ L

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