8. how many milliliters of solution is needed to make use 48.0 g calcium sulfide to make a 0.250
solution?

2680 mL

Explanation:

Given data:

Mass of calcium sulfide = 48 g

Molarity of solution = 0.250 M

Volume required = ?

Solution;

Number of moles = mass/molar mass

Number of moles = 48 g/72.143 g/mol

Number of moles = 0.67 mol

Volume:

Molarity = number of moles / volume in litter

Volume in litter = number of moles / Molarity

Volume in litter = 0.67 mol /0.250 M

Volume in litter = 2.68 L

Litter to mL:

2.68L × 1000 mL/1 L= 2680 mL

i think the answer is terrae but not 100 percent sure. ▓▬▬ §