Assuming that gasoline is 100% isooctane, that isooctane burns to produce only co2 and h2o, and that the density of isooctane is 0.792 g/ml, what mass of co2 (in kilograms) is produced each year by the annual u. s. gasoline consumption of 4.6×1010l?

1.12 × 10¹¹ kg of CO₂

Explanation:

Let's consider the combustion of isooctane.

C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)

We can establish the following relations:

Then, for 4.6 × 10¹⁰ L of gasoline (assuming that gasoline is 100% isooctane):

they emit helium gas that attaches to nearby planets.

they remove low-mass elements from the planets’ crust.

they cause nuclear fusion inside the inner core of planets.

they produce heavy elements such as iron and gold.

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :