Answers: 1
)-![pH=pK_{a}(HA)+log\frac{[A^{-}]}{[HA]}](/tpl/images/0383/9401/34f32.png)
![[A^{-}]](/tpl/images/0383/9401/fe74d.png)
and [HA] represents concentration (in molarity) of 
![\frac{[A^{-}]}{[HA]}=\frac{\frac{n_{A^{-}}}{V_{solution}in liter}}{\frac{n_{HA}}{V_{solution}in liter}}=\frac{\frac{1 mol}{10 L}}{\frac{1mol}{10L}}=1](/tpl/images/0383/9401/ac2ca.png)
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Aph 4 buffer solution is prepared by dissolving one mole of a weak acid ha (pka = 4.0) and one mole...
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