4.41 g of propane gas (c3h8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below. the calorimeter (including the water) has a heat capacity of 97.1 kj/°c. c3h8(g) + 5 o2(g)  3 co2(g) + 4 h2o() (a) if the temperature rose from 25.000°c to 27.282°c, what is the heat of the reaction, qrxn?

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

where,

= heat released by the reaction = ?

= heat absorbed by the calorimeter

= specific heat of calorimeter =

= change in temperature =

Now put all the given values in the above formula, we get:

As,

So,

Thus, the heat of the reaction is -221.6 kJ

thats how its supposed to be

sure im new too!

explanation: