Acell composed of a platinum indicator electrode and a silver-silver chloride reference electrode in a solution containing both and has a cell potential of v. if the silver-silver chloride electrode is replaced with a saturated calomel electrode (sce), what is the new cell potential?

Explanation:

Let us assume that the solution contains both and which has a cell voltage of 0.719 V.

Therefore, voltage of cell contains both Ag/AgCl reference electrode where electrode is 0.719 V.

As, = 0.719 V

It is known that potential of the silver-silver chloride reference electrode is 0.197 V.

Hence, = 0.197 V. Now, calculate as follows.

            = 0.719 V

            = 0.719 V

            = 0.916 V

Now, voltage of the cell that contains both calomel reference electrode and electrode as follows.

= calomel electrode = 0.241 V  

           Voltage of cell =

                                     = 0.916 V - 0.241 V

                                     = 0.675 V

Thus, we can conclude that 0.675 V is the new voltage.

these nuts

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.