the volume of a gas at stp is 7.30 l. what is the quantity of gas in this sample?

The quantity of gas is  0.33 mol.

Explanation:

Given data:

Volume of gas = 7.30 L

Pressure of gas = 1 atm

Temperature of gas = 273 K

Amount of gas = ?

Solution:

PV = nRT

n = PV/ RT

n = 1 atm. 7.30 L / 0.0821 atm. L. mol⁻¹. K⁻¹ × 273 K

n  = 7.30 atm. L / 22.4 atm. L. mol⁻¹

n = 0.33 mol

0.326 moles

We are given;

We are supposed to determine the quantity of the gas sample;

In this case;

1 mole = 22.4 L

Therefore;

Therefore,

Moles of the gas sample = 7.30 L ÷ 22.4 L

                                        = 0.326 moles

Therefore, the quantity of the gas sample is 0.326 moles

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error