Chemistry, 19.11.2019 02:31 marlenemedina247
Amixture of 15.0 g of the anesthetic halothane (c2hbrclf3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 torr. what are the partial pressures of each gas? a. phalothane = 778 torr, po2 = 84 torr b. phalothane = 162 torr, po2 = 700 torr c. phalothane = 84 torr, po2 = 778 torr d. phalothane = 155 torr, po2 = 707 torr e. phalothane = 707 torr, po2 = 155 torr.
Answers: 3
and 
are, 84 torr and 778 torr respectively.
= partial pressure of gas
= total pressure of gas
= mole fraction of gas
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Amixture of 15.0 g of the anesthetic halothane (c2hbrclf3 197.4 g/mol) and 22.6 g of oxygen gas has...
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