Achemist mixes 1.00 g cucl2 with an excess of (nh4)2hpo4 in dilute aqueous solution . he measures the evolution of 670 j of heat as the two substances react to give cu3(po4)2(s). compute the δh that would result from the reaction of 1.00 mo! cucl2 with an excess of (nh4)2hpo4.

will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of = 134.45 g/mol

So, 1.00 g of = of = 0.00744 mol of

0.00744 mol of produces 670 J of heat

So, 1 mol of produces of heat or 90054 J of heat

the ratio of the conjugate base to the acid required to attain the desired ph.

your answer is c) plasma

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