Give the quantum number set for one electron in the 3p sublevel of a sulfur (s) atom.

sulfurs electronic configuration is 1s2 2s2 2p6 3s2 3p4 so for the 3p sublevel principal quantum no - 3 angulum quantum no - 1 magnetic quantum no - (-1) or 0 or (-1) spin quantum no - (+1/2) or (-1/2) so the quantum numbers will be [ 3 , 1, -1 , +1/2 ] or [ 3 , 1, -1 , -1/2 ] [ 3 , 1, 0 , +1/2 ] or [ 3 , 1, 0 , -1/2 ] [ 3 , 1, 1 , +1/2 ] or [ 3 , 1, 1 , -1/2 ]
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