Asolution is prepared by mixed by mixing 0.10l of 0.14m sodium chloride with 0.21l of a 0.19m mgcl2 solution. what volume of 0.21m silver nitrate is required to precipitate all the cl- ion in the solution agcl?

Explanation:

If is the molarity and is the molarity of a given solution,

number of moles of the solute in the solution is .

Number of moles of ions in the initial solution is the sum of number of moles of ions  in and

Number of moles of ions in is

number of moles of ions  in is

Number of moles of ions in the initial solution is

So, of ions are required to displace of ions.

So,number of moles of required is

So,

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: