How many atoms are in 0.750 moles in zinc?

4.52 × 10^23 atoms

Explanation:

Concept being tested: Moles and Avogadro's number

From the question we are given;

Number of moles of Zinc = 0.750 moles

We are required to calculate the number of atoms of Zinc

In order to answer the question, we need to know that a mole of an element contains atoms equivalent to the Avogadro's number.The Avogadro's number is 6.022 × 10^23.

Therefore;

1 mole of Zinc = 6.022 × 10^23 atoms

To calculate the number of atoms we need to multiply the number of moles with the Avogadro's constant.

 = 0.750 moles × 6.022 × 10^23 atoms

= 4.52 × 10^23 atoms

Therefore; 0.750 moles of Zinc contains 4.52 × 10^23 atoms

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

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