3. identify the oxidizing agent in each of the fol-
lowing reactions.
a) cu2+ (aq) + mg(s) + cu(s) + mg2+(aq)
b) fe, o3(s) + 3co(g) → 2fe(1) + 3co,(g)

Cu

Fe

Explanation:

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

a) Cu²⁺ (aq) + Mg(s) + Cu(s) + Mg²⁺(aq)

Copper is oxidizing agent it accept two electrons from magnesium and oxidize the Mg and itself get reduced.

b) Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)

In this reaction iron is oxidizing agent because iron itself reduced from +3 to 0.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.