Chemistry, 14.11.2019 06:31 AreYouMyNewDad

1. ch4 + 202 co2 + 2h20

if you begin with 40g of ch4 and it reacts with 15g of 202 producing

20g of co2, how many grams of 2h20 are produced?

Answers: 1

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Answer from: u8p4

16.36 grams

Explanation:

From the reaction equation:

CH4 + 2O2 CO2 + 2H2O

1 : 2 1 : 2

If 20g of CO2 was produced, then the number of moles of CO2 is given by :

Molar mass of CO2 = 12 + [2 x 16]

= 44 gram/moles

Number of moles = Mass in gram/ Molar mass

= 20/ 44

= 0.4545 moles

if 0.4545 moles of CO2 were produced, then according to the equation of reaction, then:

Number of moles of H2O produced will be = 2 x 0.4545

= 0.909moles

Molar Mass of H2O = [1 x2] + [16]

= 18 grams/ mol

The mass of H2O produced will be = Number of moles x Molar Mass

= 0.909 moles x 18 grams/mole

= 16.362 grams

≈ 16.36 grams

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

Answer from: Quest

Ithink is a because if say increased in electronegativity

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1. ch4 + 202 co2 + 2h20

if you begin with 40g of ch4 and it reacts with 15g of 202 prod...