Ask your teacher sodium hydroxide solution is usually standardized by titrating a pure sample of potassium hydrogen phthalate (khc8h4o4, often abbreviated khp), an acid with one acidic hydrogen and a molar mass of 204.220 g/mol. it takes 36.01 ml of a sodium hydroxide solution to titrate a 0.1182-g sample of khp. what is the molarity of the sodium hydroxide

0.0161 M

Explanation:

Moles of KHP :

Given, Mass of KHP = 0.1182 g  

Molar mass of KHP = 204.22 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the reaction shown below:

KHP + NaOH ⇒ KNaP + H₂O

1 mole of KHP reacts with 1 mole of NaOH

So,

of KHP reacts with of NaOH

Moles of NaOH =

Volume = 36.01 mL = 0.03601 L ( 1 mL = 0.001 L)

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it should be all of them because it asks if you included all of those in your answer

explanation: