7.23 th e condensation reaction of acetone, (ch3)2co (propanone), in aqueous solution is catalyzed by bases, b, which react reversibly with acetone to form the carbanion c3h5o−. th e carbanion then reacts with a molecule of acetone to give the product. a simplifi ed version of the mechanism is (1) ah + b → bh+ + a− (2) a− + bh+ → ah + b (3) a− + ha → product where ah stands for acetone and a− its carbanion. use the steadystate approximation to fi nd the concentration of the carbanion and derive the rate equation for the formation of the product.

Explanation:

The multiple steps are:

1)

2)

3)

For carbanion (A⁻) the rate law will be

...(4)

As here B is in intermediate

so we may apply Steady state approximation (SSA) on it.

....(5)

Put this in above expression (4)

Thus

This is rate equation for formation of product

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