A) what is the volume of 6•10^22 methane molecules in normal state?
b) what is the volume of 6•10^22chlorine molecules in normal state?

A) volume of methane = 2.2 l

B) volume of Cl₂ = 2.2 l

Explanation:

A) Given data

   Number of molecules of methane = 6×10²²

Solution

first we find out the number of moles of methane

     number of moles = Number of molecules / Avogadro number

number of moles = 6×10²² / 6.02×10²³

number of moles = 0.1 mol

Now we find out the mass of methane

        mass = moles × molar mass

mass of methane = 0.1 mol × 16.04 g/mol

mass of methane = 1.6 g

now we convert it into volume

         volume = mass / density

density of methane = 0.72 g/l⁻

volume of methane = 1.6 g / 0.72 g.l⁻

volume of methane = 2.2 l

B) Given data

   Number of molecules of chlorine = 6×10²²

Solution

first we find out the number of moles of chlorine

     number of moles = Number of molecules / Avogadro number

number of moles = 6×10²² / 6.02×10²³

number of moles = 0.1 mol

Now we find out the mass of chlorine

        mass = moles × molar mass

Molar mass of Cl₂ = 70.9 g/mol

mass of Cl₂ = 0.1 mol × 70.9 g/mol

mass of Cl₂ = 7.1 g

now we convert it into volume

         volume = mass / density

density of Cl₂ = 3.2 g/l

volume of Cl₂ = 7.1 g / 3.2 g.l⁻

volume of Cl₂ = 2.2 l

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