How much heat is absorbed during production of 147 g of no by the combination of nitrogen and oxygen?
n2(g)+o2(g)→2no(g), δh = + 43 kcal/molhow much heat is absorbed during production of 147 g of no by the combination of nitrogen and oxygen?
n2(g)+o2(g)→2no(g), δh = + 43 kcal/mol

Explanation:

MM:                        30.01

            N₂ + O₂ ⟶ 2NO; ΔH = +43 kcal/mol

m/g:                         147

Treat the heat as if it were a reactant in the reaction. Then you can write

N₂ + O₂ + 43 kcal ⟶ 2NO

The conversion factor is then 43 kcal/2 mol NO.

1. Moles of NO

2. Amount of heat

the answer is na (sodium)