8.00 ml of nh3 is titrated directly from 32.6 ml of 0.4000 m hcl what is the concentration of the nh3 in the solution

1.63 M

The reaction between NH₃ and HCl is given by the equation;

NH₃(aq) + HCl(aq) → NH₄Cl(aq)

We want to calculate the concentration of ammonia solution.

Step 1: Calculate the number of moles of HCl used

To calculate the number of moles we multiply the molarity of HCl by the volume.

Moles = Molarity × Volume

          = 0.40 M × 0.0326 L

          = 0.01304 moles

Step 2: Determine the number of moles of NH₃

From the equation 1 mole of HCl reacts 1 mole of NH₃

Therefore, the mole ratio of HCl to NH₃ id 1 : 1

Hence, the number of moles of HCl are equal to the number of moles of NH₃

Number of moles of NH₃ = 0.01304 moles

Step 3: Calculate the concentration of NH₃

Molarity is the concentration of a solution in moles per liter

Molarity = Number of moles ÷ Volume

Number of moles = 0.01304 moles

Volume of NH₃ =8.00 mL or 0.008 L

Therefore;

Molarity = 0.01304 moles ÷ 0.008 L

            = 1.63 M

Therefore, the concentration of NH₃ IS 1.63 M

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

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