The stopcock connecting a 1.83 l bulb containing helium gas at a pressure of 2.60 atm, and a 6.48 l bulb containing xenon gas at a pressure of 3.56 atm, is opened and the gases are allowed to mix. assuming that the temperature remains constant, what is the final pressure in the system is atm?

P(final) = 6.16 atm

Explanation:

Solution:

According to the Dalton's law of partial pressure,

"The total pressure exerted by the mixture of gases is the sum of partial pressure of the individual gases"

P(total) = P₁ + P₂ + P₃ +Pₙ

Given data:

Pressure of helium gas = 2.60 atm

Volume of 1st bulb = 1.83 L

Pressure of xenon gas = 3.56 atm

Volume of 2nd bulb = 6.48 L

Final pressure after mixing of gases=?

Formula:

P(final) = P(helium) + P(xenon)

P(final) = 2.60 atm  + 3.56 atm

P(final) = 6.16 atm

the answer for sodium is 0.186

the answer for rubidium is 0.251