Consider the following balanced equation cac2(s) + 2h2o(i) → ca(oh)2(s) + c2h2(g)
when 1.50 mol of cac2 are allowed to react, how many moles of ca(oh)2 is
produced?

1.50 moles of  CaC₂ will produced 1.50 moles of Ca(OH)₂ .

Explanation:

Given data:

Moles of CaC₂ = 1.50 mol

Moles of Ca(OH)₂ = ?

Solution:

First of all we will write the balanced chemical equation.

CaC₂  + 2H₂O   →  Ca(OH)₂ + C₂H₂

Now we will compare the moles of CaC₂  with Ca(OH)₂ from balanced chemical equation.

                       CaC₂      :       Ca(OH)₂

                        1            :           1

                       1.50       :          1.50

1.50 moles of  CaC₂ will produced 1.50 moles of Ca(OH)₂ .

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.