Now, find the concentration of h+ ions to oh-ions listed
in table b of your student guide for a solution at a ph =
11. then divide the h+ concentration by the oh-
concentration. record these concentrations and ratio in
table c.

1. Hydrogen ion concentration [H+] = 1x10^-11 M

2. Hydroxide ion concentration [OH-] = 1x10^-3 M

3. The ratio of hydrogen ion concentration [H+] to hydroxide ion concentration [OH-] = 1x10^-8

Explanation:

Data obtained from the question include:

pH = 11

1. We can obtain the hydrogen ion concentration [H+] of the solution as follow:

pH is the negative logarithm of the hydrogen ion concentration of a solution. It is represented mathematically by the formula:

pH = - log [H+]

Now, with the above formula, the pH can be obtained as follow:

11 = - log [H+]

Divide both side by - 1

-11 = log [H+]

Take the anti - log of - 11

[H+] = 1x10^-11 M

2. Hydroxide ion concentration [OH-] can be obtained as follow:

[H+] x [OH-] = 1x10^-14 M^2

[H+] = 1x10^-11 M

1x10^-11 x [OH-] = 1x10^-14 M^2

Divide both side by 1x10^-11

[OH-] = 1x10^-14 M^2 /1x10^-11 M

[OH-] = 1x10^-3 M

3. The ratio of hydrogen ion concentration [H+] to hydroxide ion concentration [OH-] is given below:

[H+] : [OH-] = [H+] / [OH-] = 1x10^-11/1x10^-3 = 1x10^-8

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

explanation: