10) a balloon was filled to 1.25 lat 25.2°c. 0.235 g of helium was used to fill it. what is the pressure?
r = 0.08206 l. atm/°c-mole.

P = 0.1 atm

Explanation:

Given data:

Volume = 1.25 L

Temperature = 25.2 °C

Mass of gas = 0.235 g

R = 0.08206 L. atm/°C. mol

Pressure = ?

Solution:

first of all we will calculate the number of moles.

Number of moles = mass / molar mass

Number of moles = 0.235 g/  4g/mol

Number of moles =  0.06 mole

For pressure:

PV = nRT

P = nRT / V

P = 0.06 mol × 0.08206 L. atm/°C. mol × 25.2°C / 1.25 L

P = 0.124 L. atm / 1.25 L

P = 0.1 atm

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