If 30.0 g absorbs 255 j of heat, how much does the temperature of the water change? would the temperature be increasing or decreasing?

Change in temperature = 2.03°C, the temperature is increasing

In this case;

Mass of water = 30.0 g

Quantity of heat absorbed = 255 J

Specific heat capacity of water = 4.186 J/g°C

Rearranging the formula, Δt = Q ÷ mc

Δt = 255 J ÷ (4.186 J/g°C×30.0 g )

  = 2.03 °C

The temperature change is 2.03°C, the temperature is therefore increasing.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa