1.which two electron configurations represent elements that would have similar chemical properties? i.1s22s22p4ii.1s22s22p5iii.[ar]4s23 d104p3iv. [ar]4s23d104p4a) iand iib) i and iiic) iand ivd) iiand ive) iiand ii

Option C=  1 and 1V

Explanation:

The first one is the electronic configuration of oxygen.

O₈ =1s² 2s² 2p⁴

The IV is the electronic configuration of Selenium.

Se₄ =[Ar] 4s² 3d¹⁰ 4p⁴

Oxygen and selenium both are present in group 16. The elements present in same group showed similar chemical properties.

While the II is the electronic configuration of fluorine:

F₉ =1s² 2s² 2p⁵

and the III is the electronic configuration of arsenic.

Ar₃₃ = [Ar] 4s² 3d¹⁰ 4p³

Arsenic is present in group fifteen and fluorine is present in group 17. That's why their properties are not similar with each other and also with oxygen and selenium.

the solar system used to have much dust particles option no d

it is the most commonly accepted one