90.0 ml of h2o is initially at room temperature (22.0∘c). a chilled steel rod at 2.0∘c is placed in the water. if the final temperature of the system is "21.1" ∘c, what is the mass of the steel bar? specific heat of water = 4.18 j/g⋅∘cspecific heat of steel = 0.452 j/g⋅∘c

The steel bar weighs 39.014 grams

Explanation:

Heat lost by water = - heat gained by steel

m(water) = 90 grams

m(steel) = TO BE DETERMINED

specific heat of water = 4.18 J/g°C

specific heat of steel = 0.452 J/g°C

Initial temperature T1 water = 22°C

Final temperature T2 water = 21.1 °C

Initial temperature T1 steel = 2°C

Final temperature T2 steel = 21.1°C

Heat transfer = m*Cp*ΔT

with Cp = specific heat

with ΔT = Change of temperature = T2 - T1

m(water) * Cp(water) * ΔT(water) = m(steel) *Cp(steel) *ΔT(steel)

90g * 4.18 * ( 21.1 - 22) = -m(steel) * 0.452 * (21.1-2)

-338.58  = - m(steel)*8.6784

m(steel) = 39.014 grams

The steel bar weighs 39.014 grams

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.