The specific heat capacity of thallium is 0.128 j/gc. a sample of thallium weighing 32.9 g is heated from 49c to its melting point(303 c). calculate the energy change involved.

Thallium absorbed 1069.645 J heat to reach to its melting point.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of thallium = 32.9 g

specific heat capacity of thallium = 0.128 j/g. °C

Initial temperature = 49 °C

Final temperature = 303 °C

Solution:

Change in temperature = T₂- T₁

ΔT = 303 °C - 49 °C = 254 °C

Formula:

Q = m.c. ΔT

Q = 32.9 g ×0.128 j/g. °C × 254 °C

Q = 1069.645 J

Thallium absorbed 1069.645 J heat to reach to its melting point.

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

the answer to this question is 3.